js用最简单的方法实现2个数组的交叉一对一合并

246 ℃
let data1 = [{"name": '小米'}, {"name": '小红'}, {"name": '小花'}, {"name": '小明'}];
let data2 = [
  {"school": "清北", "type": "本科"}, 
  {"school": "浙大", "type": "研究生"}, 
  {"school": "复旦", "type": "大专"}, 
  {"school": "剑桥", "type": "硕士"}
];

let result = data2.map(z=>data1.map(x=>({...x, ...z}))).flat()
console.log('输出结果:',result);
[
    {
        "name": "小米",
        "school": "清北",
        "type": "本科"
    },
    {
        "name": "小红",
        "school": "清北",
        "type": "本科"
    },
    {
        "name": "小花",
        "school": "清北",
        "type": "本科"
    },
    {
        "name": "小明",
        "school": "清北",
        "type": "本科"
    },
    {
        "name": "小米",
        "school": "浙大",
        "type": "研究生"
    },
    {
        "name": "小红",
        "school": "浙大",
        "type": "研究生"
    },
    {
        "name": "小花",
        "school": "浙大",
        "type": "研究生"
    },
    {
        "name": "小明",
        "school": "浙大",
        "type": "研究生"
    },
    {
        "name": "小米",
        "school": "复旦",
        "type": "大专"
    },
    {
        "name": "小红",
        "school": "复旦",
        "type": "大专"
    },
    {
        "name": "小花",
        "school": "复旦",
        "type": "大专"
    },
    {
        "name": "小明",
        "school": "复旦",
        "type": "大专"
    },
    {
        "name": "小米",
        "school": "剑桥",
        "type": "硕士"
    },
    {
        "name": "小红",
        "school": "剑桥",
        "type": "硕士"
    },
    {
        "name": "小花",
        "school": "剑桥",
        "type": "硕士"
    },
    {
        "name": "小明",
        "school": "剑桥",
        "type": "硕士"
    }
]

js如何实现数组合并(concat函数用法)

标签: js数组合并, js数组转换

上面是“js用最简单的方法实现2个数组的交叉一对一合并”的全面内容,想了解更多关于 js 内容,请继续关注web建站教程。

当前网址:https://m.ipkd.cn/webs_16205.html

声明:本站提供的所有资源部分来自互联网,如果有侵犯您的版权或其他权益,请发送到邮箱:admin@ipkd.cn,我们会在看到邮件的第一时间内为您处理!

layui插件可以兼容IE8浏览器吗
mysql数据库导入sql文件报错解决方法
Android开发:app里面的语音播放功能实现代码介绍
帝国cms如何做留言板功能
vue样式scoped中什么情况下用深度选择器/deep/